API now supports adding classifications by identifier instead of from a library

This commit is contained in:
Dion Moult
2022-08-02 10:09:51 +10:00
parent 8ca5dd747e
commit 21094c59d9
4 changed files with 161 additions and 34 deletions
@@ -0,0 +1,34 @@
# IfcOpenShell - IFC toolkit and geometry engine
# Copyright (C) 2022 Dion Moult <dion@thinkmoult.com>
#
# This file is part of IfcOpenShell.
#
# IfcOpenShell is free software: you can redistribute it and/or modify
# it under the terms of the GNU Lesser General Public License as published by
# the Free Software Foundation, either version 3 of the License, or
# (at your option) any later version.
#
# IfcOpenShell is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU Lesser General Public License for more details.
#
# You should have received a copy of the GNU Lesser General Public License
# along with IfcOpenShell. If not, see <http://www.gnu.org/licenses/>.
import test.bootstrap
import ifcopenshell.api
class TestAddClassification(test.bootstrap.IFC4):
def test_adding_a_classification(self):
ifcopenshell.api.run("root.create_entity", self.file, ifc_class="IfcProject")
ifcopenshell.api.run("classification.add_classification", self.file, classification="Name")
assert self.file.by_type("IfcClassification")[0].Name == "Name"
def test_adding_a_classification_from_a_library(self):
library = ifcopenshell.file()
classification = library.createIfcClassification(Name="Name")
ifcopenshell.api.run("root.create_entity", self.file, ifc_class="IfcProject")
ifcopenshell.api.run("classification.add_classification", self.file, classification=classification)
assert self.file.by_type("IfcClassification")[0].Name == "Name"