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util.schema.is_a - use c++ implementation

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Andrej730
2025-02-24 14:52:54 +05:00
parent 1d2ac9426d
commit 5fa0aa03e4
1 changed files with 1 additions and 6 deletions
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src/ifcopenshell-python/ifcopenshell/util/schema.py
+1 -6
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@@ -80,12 +80,7 @@ def is_a(declaration: ifcopenshell.ifcopenshell_wrapper.entity, ifc_class: str)
declaration = ifcopenshell.util.schema.get_declaration(wall) declaration = ifcopenshell.util.schema.get_declaration(wall)
ifcopenshell.util.schema.is_a(declaration, "IfcRoot") # True ifcopenshell.util.schema.is_a(declaration, "IfcRoot") # True
""" """
ifc_class = ifc_class.upper() return declaration._is(ifc_class)
if declaration.name_uc() == ifc_class:
return True
if declaration.supertype():
return is_a(declaration.supertype(), ifc_class)
return False
def get_supertypes( def get_supertypes(