Selector: negate list comparisons as an aggregate #8129

compare() recursed into list values passing the negated comparison through,
so != meant "at least one item differs" and both = and != matched the same
elements on any multi-valued property (e.g. an enumerated property with two
values selected). Strip the negation for the per-item comparison and negate
the aggregate instead, so != means "no item equals" and stays the complement
of =. The same applies to !*=.

Co-Authored-By: Claude Fable 5 <noreply@anthropic.com>
(cherry picked from commit 209c44db83)
This commit is contained in:
Petru Conduraru
2026-07-09 13:24:46 +03:00
committed by Dion Moult
parent ad6f9bbbf6
commit f761156dea
2 changed files with 13 additions and 1 deletions
@@ -1246,7 +1246,13 @@ class FacetTransformer(lark.Transformer):
def compare(self, element_value, comparison, value) -> bool:
if isinstance(element_value, (list, tuple)):
return any(self.compare(ev, comparison, value) for ev in element_value)
# Match if any item does, negating the aggregate rather than each
# item, so that e.g. != means "no item equals" and stays the
# complement of = (#8129).
result = any(self.compare(ev, comparison.lstrip("!"), value) for ev in element_value)
if comparison.startswith("!"):
return not result
return result
elif isinstance(value, str):
try:
if isinstance(element_value, int):