# IfcOpenShell - IFC toolkit and geometry engine # Copyright (C) 2021 Dion Moult # # This file is part of IfcOpenShell. # # IfcOpenShell is free software: you can redistribute it and/or modify # it under the terms of the GNU Lesser General Public License as published by # the Free Software Foundation, either version 3 of the License, or # (at your option) any later version. # # IfcOpenShell is distributed in the hope that it will be useful, # but WITHOUT ANY WARRANTY; without even the implied warranty of # MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the # GNU Lesser General Public License for more details. # # You should have received a copy of the GNU Lesser General Public License # along with IfcOpenShell. If not, see . import math import ifcopenshell.api import ifcopenshell.util.date import ifcopenshell.util.element import ifcopenshell.util.resource class Usecase: def __init__(self, file, resource=None): """Calculates the number of resources required to perform scheduled work on a task. """ self.file = file self.settings = {"resource": resource} def execute(self): if ifcopenshell.util.constraint.is_attribute_locked(self.settings["resource"], "Usage.ScheduleUsage"): return if ( not self.settings["resource"].Usage or not self.settings["resource"].Usage.ScheduleWork ): return task = ifcopenshell.util.resource.get_task_assignments( self.settings["resource"] ) if not task or not task.TaskTime: return if not task.TaskTime.DurationType or task.TaskTime.DurationType == "WORKTIME": hours_per_day = 8 else: hours_per_day = 24 task_duration = ifcopenshell.util.date.ifc2datetime( task.TaskTime.ScheduleDuration ) seconds = task_duration.days * hours_per_day * 60 * 60 seconds += task_duration.seconds person_hours = ifcopenshell.util.date.ifc2datetime( self.settings["resource"].Usage.ScheduleWork ) required_resources = person_hours.total_seconds() / seconds self.settings["resource"].Usage.ScheduleUsage = float(required_resources)