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JuliaFEM.jl/test/test_heat_3.jl
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Jukka Aho 5ac771480e Use package HeatTransfer.jl for heat problems (#194)
Heat transfer analysis is moved to its own package where the development continues. Two small modifications are needed for test files:

- Instead of `problem.properties.formulation`, we have two separate problems, `PlaneHeat` for two-dimensional problems and `Heat` for three-dimensional problems.
- Unnecessary prefixing of field names is changed. For example, now we simply have only "thermal conductivity" and not prefixed "temperature thermal conductivity".
2018-05-03 15:37:37 +03:00

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# This file is a part of JuliaFEM.
# License is MIT: see https://github.com/JuliaFEM/JuliaFEM.jl/blob/master/LICENSE.md
using JuliaFEM
using JuliaFEM.Preprocess
using JuliaFEM.Postprocess
using JuliaFEM.Testing
@testset "2d poisson problem with known analytical solution" begin
# from FENiCS tutorial, u(x,y) = 1 + x² + 2y² on [0x1]×[0,1]
# and u₀(x,y) = 1 + x² + 2y², f(x,y) = -6
mesh_file = @__DIR__()*"/testdata/primitives.med"
mesh = aster_read_mesh(mesh_file, "UNITSQUARE_6X4")
field = Problem(PlaneHeat, "unit square, 6x4 triangular mesh", 1)
field.elements = create_elements(mesh, "UNITSQUARE")
update!(field, "thermal conductivity", 1.0)
update!(field, "heat source", -6.0)
bc = Problem(Dirichlet, "u₀(x,y) = 1 + x² + 2y²", 1, "temperature")
#bc.properties.order = 2
#bc.properties.dual_basis = true
bc.properties.variational = false
bc.elements = create_elements(mesh, "FACE1", "FACE2", "FACE3", "FACE4")
function u0(element, ip, time)
x, y = element("geometry", ip, time)
return 1 + x^2 + 2*y^2
end
update!(bc, "temperature 1", u0)
solver = LinearSolver(field, bc)
solver()
T_fem = Float64[]
T_acc = Float64[]
for (nid, X) in field("geometry", 0.0)
push!(T_fem, field("temperature", X)[1])
push!(T_acc, 1.0 + X[1]^2 + 2*X[2]^2)
end
@test maximum(abs.(T_fem-T_acc)) < 1.0e-12
# gradient of field is
gradT(X) = [2*X[1] 4*X[2]]
X = [0.5, 0.5]
gradT1 = gradT(X)
gradT2 = field("temperature", X, 0.0, Val{:Grad})
info("gradT1 = $gradT1, gradT2 = $gradT2")
# [1.1666666666666625 1.5000000000000018] quite big difference ..?
@test isapprox(gradT1, gradT2; rtol=25.0e-2)
end