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using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using Autodesk.CodeChecking.Concrete;

namespace ConcreteCalculationsExample
{
   partial class Example
   {
         
      /// <summary>
      /// Case 8: Calculation of internal forces in asymmetric section for given state of strain with horizontal neutral axis
      /// </summary>
      public void Case8()
      {
         // geometry definition
         Geometry geometry = new Geometry();
         geometry.Add(0.0, 0.0);
         geometry.Add(0.0, 0.3);
         geometry.Add(0.2, 0.3);
         geometry.Add(0.2, 0.7);
         geometry.Add(0.9, 0.7);
         geometry.Add(0.9, 0.5);
         geometry.Add(0.5, 0.5);
         geometry.Add(0.5, 0.0);

         // rebars definition
         List<Rebar> rebars = new List<Rebar>();
         rebars.Add(new Rebar(0.05, 0.05, 0.025 * 0.025 * Math.PI / 4.0));
         rebars.Add(new Rebar(0.45, 0.05, 0.025 * 0.025 * Math.PI / 4.0));
         rebars.Add(new Rebar(0.85, 0.55, 0.012 * 0.012 * Math.PI / 4.0));
         rebars.Add(new Rebar(0.85, 0.65, 0.012 * 0.012 * Math.PI / 4.0));
         rebars.Add(new Rebar(0.45, 0.65, 0.012 * 0.012 * Math.PI / 4.0));
         rebars.Add(new Rebar(0.25, 0.65, 0.012 * 0.012 * Math.PI / 4.0));
         rebars.Add(new Rebar(0.25, 0.05, 0.025 * 0.025 * Math.PI / 4.0));
         rebars.Add(new Rebar(0.05, 0.25, 0.012 * 0.012 * Math.PI / 4.0));
         rebars.Add(new Rebar(0.45, 0.25, 0.012 * 0.012 * Math.PI / 4.0));
         rebars.Add(new Rebar(0.25, 0.55, 0.012 * 0.012 * Math.PI / 4.0));
         // concrete parameters
         Concrete concrete = new Concrete();
         concrete.SetStrainStressModelRectangular(50e6, 0.0035, 37e9, 0.8);
         // steel parameters
         Steel steel = new Steel();
         steel.SetModelIdealElastoPlastic(500e6, 0.075, 200e9);
         // solver creation and parameterization
         RCSolver solver = RCSolver.CreateNewSolver(geometry);
         solver.SetRebars(rebars);
         solver.SetConcrete(concrete);
         solver.SetSteel(steel);
         //calulation
         solver.SolveForces(ResultType.Section, 0.0035, -0.00875);
         // result for rebars
         SetOfForces forcesRebar = solver.GetInternalForces(ResultType.Rebars);
         // result for concrete
         SetOfForces forcesConcrete = solver.GetInternalForces(ResultType.Concrete);
         Point2D Gcc = solver.GetStressGravityCenter(ResultType.Concrete);
         double Acc = solver.GetConcreteStressArea();
         // result for RC section
         SetOfForces forces = solver.GetInternalForces(ResultType.Section);
         // result presentation
         sb.AppendLine();
         sb.AppendLine(decoration);
         sb.AppendLine("Case 8: Calculation of internal forces in asymmetric section for given state of strain with horizontal neutral axis");
         sb.AppendLine(decoration);
         sb.AppendLine(FormatOutput("Ns",forcesRebar.AxialForce,6));
         sb.AppendLine(FormatOutput("Mxs" , forcesRebar.MomentX,6));
         sb.AppendLine(FormatOutput("Mys",forcesRebar.MomentY,6));
         sb.AppendLine(FormatOutput("Ac",Acc,6));
         sb.AppendLine(FormatOutput("Gcx",Gcc.X,6));
         sb.AppendLine(FormatOutput("Gcy",Gcc.Y,6));
         sb.AppendLine(FormatOutput("Nc",forcesConcrete.AxialForce,6));
         sb.AppendLine(FormatOutput("Mxc" , forcesConcrete.MomentX,6));
         sb.AppendLine(FormatOutput("Myc",forcesConcrete.MomentY,6));
         sb.AppendLine(FormatOutput("N",forces.AxialForce,6));
         sb.AppendLine(FormatOutput("Mx" , forces.MomentX,6));
         sb.AppendLine(FormatOutput("My",forces.MomentY,6));
      }
   }
}