IfcParse: don't strip delimiters from a single-character token #5683

asStringRef removes the first and last characters of a string, enumeration
or binary token to drop the delimiters, guarded only by !str.empty(). A
malformed single-character token (e.g. a bare '.' left when a fuzzer turns
'.PHYSICAL.' into '.)HYSICAL.') has length 1, so the first erase empties the
string and the second erase(str.begin()) runs on an empty string. That is
undefined behaviour: benign on a normal build, but it aborts (or throws
std::length_error from a later append) under a hardened libstdc++ with
_GLIBCXX_ASSERTIONS, which is why this file only segfaulted on the Fedora
build. Require at least two characters before stripping.

Co-Authored-By: Claude Fable 5 <noreply@anthropic.com>
This commit is contained in:
Petru Conduraru
2026-07-06 08:19:57 +03:00
committed by Thomas Krijnen
parent 5e539890f1
commit d2381ad6c6
+8 -1
View File
@@ -449,7 +449,14 @@ const std::string& TokenFunc::asStringRef(const Token& token) {
}
std::string& str = token.lexer->GetTempString();
token.lexer->TokenString(token.startPos, str);
if ((isString(token) || isEnumeration(token) || isBinary(token)) && !str.empty()) {
// A well-formed string/enumeration/binary token has both delimiters (e.g.
// '...', .XXX., "...."), so at least two characters. Malformed input from a
// fuzzer can produce a single-character token (e.g. a bare '.' left by
// ".)" instead of ".PHYSICAL."); stripping both ends would then erase past
// the end of an already-empty string, which is undefined behaviour and
// aborts under hardened standard libraries (_GLIBCXX_ASSERTIONS). Require
// two characters before stripping. See #5683.
if ((isString(token) || isEnumeration(token) || isBinary(token)) && str.size() >= 2) {
//remove start+end characters in-place
str.erase(str.end() - 1);
str.erase(str.begin());